How many pounds of any material are needed to achieve 1 part per million in 1 acre-foot of water?

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To determine how many pounds of material are required to achieve a concentration of 1 part per million (ppm) in 1 acre-foot of water, it's essential to understand what 1 ppm represents in terms of weight and volume.

One part per million means one part of a substance for every million parts of the total solution. In water, 1 ppm is equivalent to 1 milligram of a substance per liter of water. An acre-foot is a unit of volume that represents a foot of water covering an area of one acre.

An acre-foot of water contains approximately 325,851 gallons or 1,233,500 liters. To find out how many pounds are necessary for 1 ppm in this volume, you first convert the 1 ppm requirement from milligrams to pounds:

1 mg/L * 1,233,500 L = 1,233.5 grams of chemical per acre-foot.

Next, converting grams to pounds involves knowing that there are about 453.592 grams in a pound. Thus:

1,233.5 grams ÷ 453.592 grams/lb ≈ 2.72 lbs.

The figure is rounded to 2.7 pounds, which aligns with the scientific understanding of

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